LeetCode#121. Best Time to Buy and Sell Stock
Table of Contents
Problem Statement
You are given an array prices
where prices[i]
is the price of a given stock on the ith
day.
You want to maximize your profit by choosing a single day to buy one stock and choosing a different day in the future to sell that stock.
Return the maximum profit you can achieve from this transaction. If you cannot achieve any profit, return 0
.
Example 1:
Input: prices = [7,1,5,3,6,4] Output: 5 Explanation: Buy on day 2 (price = 1) and sell on day 5 (price = 6), profit = 6-1 = 5. Note that buying on day 2 and selling on day 1 is not allowed because you must buy before you sell.
Example 2:
Input: prices = [7,6,4,3,1] Output: 0 Explanation: In this case, no transactions are done and the max profit = 0.
Constraints:
1 <= prices.length <= 105
0 <= prices[i] <= 104
Golang Solution
func maxProfit(prices []int) int {
start := 0
maxProfit := 0
if len(prices) > (10*10*10*10*10){
return 0
}
for i:=1; i < len(prices); i++ {
if prices[i] > (10*10*10*10){
return 0
}
if prices[start] > prices[i]{
start = i
}else if maxProfit < (prices[i]-prices[start]){
maxProfit = prices[i]-prices[start]
}
}
return maxProfit
}
Time Complexity
- O(n) since we are iterating through the array once.
Space Complexity
- O(1) since we only use a few variables to track the maxprofit .
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