Table of Contents
Problem Statement
You are given an integer n
representing the size of a 0-indexed memory array. All memory units are initially free.
You have a memory allocator with the following functionalities:
- Allocate a block of
size
consecutive free memory units and assign it the idmID
. - Free all memory units with the given id
mID
.
Note that:
- Multiple blocks can be allocated to the same
mID
. - You should free all the memory units with
mID
, even if they were allocated in different blocks.
Implement the Allocator
class:
Allocator(int n)
Initializes anAllocator
object with a memory array of sizen
.int allocate(int size, int mID)
Find the leftmost block ofsize
consecutive free memory units and allocate it with the idmID
. Return the block’s first index. If such a block does not exist, return-1
.int freeMemory(int mID)
Free all memory units with the idmID
. Return the number of memory units you have freed.
Example 1:
Input ["Allocator", "allocate", "allocate", "allocate", "freeMemory", "allocate", "allocate", "allocate", "freeMemory", "allocate", "freeMemory"] [[10], [1, 1], [1, 2], [1, 3], [2], [3, 4], [1, 1], [1, 1], [1], [10, 2], [7]] Output
[null, 0, 1, 2, 1, 3, 1, 6, 3, -1, 0]
Explanation
Allocator loc = new Allocator(10); // Initialize a memory array of size 10. All memory units are initially free.
loc.allocate(1, 1); // The leftmost block's first index is 0. The memory array becomes [1,_,_,_,_,_,_,_,_,_]. We return 0.
loc.allocate(1, 2); // The leftmost block's first index is 1. The memory array becomes [1,2,_,_,_,_,_,_,_,_]. We return 1.
loc.allocate(1, 3); // The leftmost block's first index is 2. The memory array becomes [1,2,3,_,_,_,_,_,_,_]. We return 2.
loc.freeMemory(2); // Free all memory units with mID 2. The memory array becomes [1,_, 3,_,_,_,_,_,_,_]. We return 1 since there is only 1 unit with mID 2.
loc.allocate(3, 4); // The leftmost block's first index is 3. The memory array becomes [1,_,3,4,4,4,_,_,_,_]. We return 3.
loc.allocate(1, 1); // The leftmost block's first index is 1. The memory array becomes [1,1,3,4,4,4,_,_,_,_]. We return 1.
loc.allocate(1, 1); // The leftmost block's first index is 6. The memory array becomes [1,1,3,4,4,4,1,_,_,_]. We return 6.
loc.freeMemory(1); // Free all memory units with mID 1. The memory array becomes [_,_,3,4,4,4,_,_,_,_]. We return 3 since there are 3 units with mID 1.
loc.allocate(10, 2); // We can not find any free block with 10 consecutive free memory units, so we return -1.
loc.freeMemory(7); // Free all memory units with mID 7. The memory array remains the same since there is no memory unit with mID 7. We return 0.
Constraints:
1 <= n, size, mID <= 1000
- At most
1000
calls will be made toallocate
andfreeMemory
.
Logic
- The finding free slot work can be simplified using sliding window approach
- Always start with sliding window logic for size of k and array is present in problem.
- Use map for future free operations.
Golang code
/**
* Your Allocator object will be instantiated and called as such:
* obj := Constructor(n);
* param_1 := obj.Allocate(size,mID);
* param_2 := obj.FreeMemory(mID);
*/
type Allocator struct {
arr []int
memoryMap map[int][]int
totalFreeSlot int
totalSlot int
}
func Constructor(n int) Allocator {
return Allocator{
arr: make([]int, n),
memoryMap: make(map[int][]int),
totalSlot: n,
totalFreeSlot: n,
}
}
func (this *Allocator) Allocate(size int, mID int) int {
if this.totalFreeSlot < size {
return -1
}
start := -1
freeSlotCounter := 0
// sliding windows approach
// keep it simple
for i := 0; i < this.totalSlot; i++ {
if this.arr[i] == 0 {
if start == -1 {
start = i
}
freeSlotCounter++
if freeSlotCounter == size {
// allocate memory for mID
for j := start; j < start+size; j++ {
this.arr[j] = mID
this.memoryMap[mID] = append(this.memoryMap[mID], j)
}
this.totalFreeSlot -= size
return start
}
} else {
start = -1
freeSlotCounter = 0
}
}
return -1
}
func (this *Allocator) FreeMemory(mID int) int {
freedMemory := 0
if values, exist := this.memoryMap[mID]; exist {
// reset the memory units
for _, value := range values {
this.arr[value] = 0
}
freedMemory = len(values)
// update free slot counter
this.totalFreeSlot += freedMemory
// free up the memory
delete(this.memoryMap, mID)
}
return freedMemory
}
Output
Input
["Allocator","allocate","allocate","allocate","freeMemory","allocate","allocate","allocate","freeMemory","allocate","freeMemory"]
[[10],[1,1],[1,2],[1,3],[2],[3,4],[1,1],[1,1],[1],[10,2],[7]]
Output
[null,0,1,2,1,3,1,6,3,-1,0]
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